-14x^2-39x-10=0

Solution for -14x^2-39x-10=0 equation:

-14x^2-39x-10=0

a = -14; b = -39; c = -10;
Δ = b2-4ac
Δ = -392-4·(-14)·(-10)
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{961}=31$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-39)-31}{2*-14}=\frac{8}{-28}
=-2/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-39)+31}{2*-14}=\frac{70}{-28}
=-2+1/2
$